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Unit 8 Further Engineering Mathematics BTEC Level 3 Assignment Answers UK

The BTEC Level 3 Unit 8 Further Engineering Mathematics assignment delves into advanced mathematical concepts crucial for engineering applications. Topics typically include differential equations, vector calculus, complex numbers, and Fourier transforms, among others. This unit equips students with the mathematical tools necessary for analysing and solving complex engineering problems encountered in various fields such as mechanical, electrical, and civil engineering. Through practical exercises and theoretical understanding, students develop proficiency in mathematical techniques essential for engineering design, analysis, and research.

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Assignment Task 1: Trigonometric Functions in Engineering

Trigonometric functions play a crucial role in engineering, particularly in the analysis of mechanical systems, electrical circuits, and structural design. For this task, we will examine a scenario involving the calculation of forces acting on a structure using trigonometric principles.

Scenario:

A bridge is subjected to a load of 5000 Newtons at an angle of 30 degrees to the horizontal. Calculate the horizontal and vertical components of the force exerted on the bridge.

Solution:

To find the horizontal and vertical components of the force, we use trigonometric functions.

Horizontal component = Force × cos(angle)

Vertical component = Force × sin(angle)

Horizontal component = 5000 N × cos(30°)
Horizontal component ≈ 5000 N × 0.866
Horizontal component ≈ 4330 N

Vertical component = 5000 N × sin(30°)
Vertical component ≈ 5000 N × 0.5
Vertical component ≈ 2500 N

Conclusion:

The horizontal component of the force exerted on the bridge is approximately 4330 Newtons, while the vertical component is approximately 2500 Newtons.

Assignment Task 2: Differential Calculus in Engineering

Differential calculus is indispensable in engineering for analysing rates of change, optimizing designs, and predicting system behaviour. Let’s explore a practical application of differential calculus in engineering.

Scenario:

A tank is being filled with water at a rate of 2 cubic meters per minute. The radius of the tank is 3 meters. Determine the rate at which the water level is rising when the depth of the water is 2 meters.

Solution:

We can use the formula for the volume of a cylinder to relate the rate of change of volume to the rate of change of height.

Volume of cylinder = π × radius² × height

Differentiating both sides with respect to time (t), we get:

dV/dt = π × 2 × radius × dh/dt

Given that dV/dt = 2 m³/min, radius = 3 m, and height (h) = 2 m, we can solve for dh/dt.

2 = π × 2 × 3 × dh/dt

dh/dt = 2 / (6π)

dh/dt ≈ 0.1061 meters per minute

Conclusion:

The rate at which the water level is rising when the depth of the water is 2 meters is approximately 0.1061 meters per minute.

Assignment Task 3: Linear Algebra in Engineering

Linear algebra finds wide applications in engineering, including solving systems of linear equations, analysing electrical circuits, and modelling mechanical systems. Let’s consider a problem involving matrix manipulation in engineering.

Scenario:

A manufacturing plant produces three types of products: A, B, and C. The cost per unit for each product is as follows:

  • Product A: £10

  • Product B: £15

  • Product C: £20

The plant produces 100 units of Product A, 150 units of Product B, and 200 units of Product C daily. Calculate the total cost of production using matrix multiplication.

Solution:

Let’s represent the cost per unit as a column matrix and the production quantities as a row matrix. Then, we can multiply these matrices to find the total cost of production.

Cost matrix:

(101520)

10

15

20

Production matrix:

(100150200)

(

100

150

200

)

Total cost = Cost matrix × Production matrix

(101520)×(100150200)

10

15

20

×(

100

150

200

)

=(10×100)+(15×150)+(20×200)

=(10×100)+(15×150)+(20×200)

=1000+2250+4000

=1000+2250+4000

=£7250

=£7250

Conclusion:

The total cost of production for the given quantities of Products A, B, and C amounts to £7250.

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